Solved Examples on Electric Field
Example 1. A force of 100 N is acting on the charge 10 μ C at any point. Determine the electric field intensity at that point.
Solution:
Given:
Force F = 100 N
Charge q = 10 μ C
Electric field formula is given by
E = F / q
E = 100N / 10×10−6C
E = 107 N/C.
2. Calculate the electric field at points P, Q for the following two cases.(figure is provided below).
(a) For a charge of +1 µC placed at the origin.
Figure of part a
The magnitude of the electric field at point P is
Ep = {1/4πε }(q/r2 )
Ep = (9 × 109 × 1 × 10-6 )/4 = 2.25 × 103 NC-1
Since, the source charges is positive, the electric field points away from the charge,
So the electric field at the point P is given by
= 2.25 × 103 NC-1
For the point Q;
EQ = 9 × 109 × 1 × 10-6/16 = 0.56 × 103 NC-1
(b)For a charge of -2 µC placed at the origin
Figure for part -b
The magnitude of the electric field at point P is
Ep = {1/4πε }(q/r2 )
Ep = (9 × 109 × 2 × 10-6)/4
Ep = 4.5 × 103 NC-1
Since, the charge is negative, the electric field points towards,
So, the electric field at point P is given by
= -4.5 × 103 NC-1
For the point Q = (9 × 109 × 1 × 10-6 )/36 = 0.5 × 103 NC-1
Electric Field
Electric field is a fundamental concept in physics, defining the influence that electric charges exert on their surroundings. This field has both direction and magnitude. It guides the movement of charged entities, impacting everything from the spark of static electricity to the functionality of electronic devices Understanding electric fields will help you to understand how charge particles interact with each other and the surroundings and guide various natural and technological phenomena. In this article, we will learn in detail about electric field, its formula, calculation of electric field for ring, straight wire and continuous charge distribution.
Table of Content
- What is an Electric Field?
- Electric Field Formula
- Electric Field Lines
- Electric Field Calculation
- How to Find the Electric Field Using Gauss Law?
- Electric Field For Continuous Charge Distribution
- Applications of Gauss Law to Find Electric Field
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