Sample Problems on Geometry Formulas

Problem 1. If the radius of a circle is 14cm. Find the area of the given circle.

Solution:

Given

Radius of the circle is 14cm.

We have,

Area of the circle (A)=πr²

=>22/7 × 14 × 14

=>616cm²

Problem 2. Find the area of a triangle with a base of 12cm and a height of 8cm.

Solution:

Given

Base of the triangle is 12cm.

Height of the triangle is 8cm.

We have,

Area of triangle(A)=1/2 × b × h

=>1/2 × 12 × 8

=>48cm²

Problem 3. Find the perimeter of the given rectangle with a length of 10cm and breadth of 4cm.

Solution:

Given

Length of the rectangle is 10cm.

Breadth of the rectangle is 4cm.

We have,

Perimeter of rectangle(P)= 2(l+b)

=>2(10+4)

=>2 × 14

=>28cm

Problem 4. Find the perimeter of a square having a length of 5cm.

Solution:

Given

Length of the square is 5cm.

We have,

Perimeter of the square(P)= 4l

=> 4 × 5

=>20cm

Problem 5. Find the volume of a sphere having a radius of 9cm.

Solution:

Given

Radius of the sphere is 9cm.

We have

Volume of a sphere(V)=4/3 πr³

=>4/3 × 22/7 × (9)³

=>3054.85cm³

Problem 6. Calculate the area of a trapezoid having bases 8cm and 10cm and height of 12cm.

Solution:

Given

Let the bases of the trapezoid be b1 and b2 with values 8cm and 10cm respectively.

Height of the trapezoid is 12cm.

We have,

Area of Trapezoid = A =1/2 × (b1 + b2) × h

=>1/2 × (8 +10) × 12

=>1/2 × 18 × 12

=>216/2

=>108cm²

Problem 7. Find the volume of the given cone having a radius of 6cm and a height of 12cm.

Solution:

Given

Radius of the cone is 6cm.

Height of the given cone is 12cm

We have,

Volume of a Cone = V = 1/2× πr²h

=>1/2 × 22/7 × (6)² × 12

=>9504/14

=>678.85cm³

Problem 8. Calculate the curved surface area of a cylinder having a radius of 4cm and a height of 8cm.

Solution:

Given

Radius of the cylinder is 4cm.

Height of the cylinder is 8cm.

We have,

Curved surface area= 2πrh

=>2 × 22/7 × 4 × 8

=>201.14cm²

Problem 9. Calculate the area of a cube box having a side of 3cm.

Solution:

Given

Length of a side is 3cm.

We have,

Area of cube(A)= 6a²

=> 6 × 3 ×3

=>54cm²

In mathematics, geometry stands as a discipline of study and subject for the analysis of shapes and structures along with their properties. The article below illustrates the standard and derived formulas of geometry for the calculation of various parameters of a particular shape. These formulas are used to determine the unknown volume, area, perimeter, length of sides and diagonals, etc.