Program to calculate pow(x,n) using math.log2() and ** operator
Here, we can use the math.log2() in combination with the operator “**” to calculate the power of a number.
Below is the implementation of the above approach.
C++
#include <cmath>#include <iostream>using namespace std;int calculatePower(int a, int n){ return round(pow(2, (log2(a) * n)));}int main(){ int a = 2; int n = 3; cout << calculatePower(a, n) << endl; return 0;} |
Output
8
Time Complexity: O(1)
Auxiliary Space: O(1)
Please refer complete article on Write program to calculate pow(x, n) for more details!
C++ Program To Calculate the Power of a Number
Write a C++ program for a given two integers x and n, write a function to compute xn. We may assume that x and n are small and overflow doesn’t happen.
Examples :
Input : x = 2, n = 3
Output : 8Input : x = 7, n = 2
Output : 49
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