Kirchhoff’s Law Solved Examples
Example 1: Find the value of I from the circuit in the figure below.
Solution:
Apply Kirchhoff’s First Law to the point P in the supplied circuit.
Consider the sign convention: positive arrows point toward P, whereas negative arrows point away from P.
As a result, we now have the following:
0.2 A – 0.4 A + 0.6 A – 0.5 A + 0.7 A – I = 0
1.5 A – 0.9 A – I = 0
0.6 A – I = 0
I = 0.6A
Example 2: Find the value of the current passing through the resistance R1 = 10 Ω in the circuit below using Kirchhoff’s principles, when R2 and R3 both are equal and their value is 5 Ω.
Solution:
Applying Kirchhoff’s Law in the above circuit, Let’s take the current ‘i’ passing through the loop in the clockwise direction
-10 + 5(i) + 5(i) + 10(i) + 5 = 0
20i -5 = 0
20i = 5
i = 5 / 20 =1/4
The current passing through R1 is 1/4 Ampere.
Also, Check
Kirchhoff’s Laws
Kirchhoff’s Laws are the basic laws used in electrostatics to solve complex circuit questions. Kirchhoff’s Laws were given by Gustav Robert Kirchhoff who was a famous German Physicist. He gave us two laws Kirchhoff’s Current Law and Kirchhoff’s Voltage Law which are discussed in this article.
These laws deal with the flow of current and the voltage applied in the complex circuit and provide a way to solve these complex circuits. In this article, we will learn about Kichhoff’s Current Law, Kirchhoff’s Voltage Law, their applications, examples, and others in detail.
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