Examples on Force Formula

Example 1: What is the frictional force on an object if the coefficient of friction is 0.50 and the normal reaction offered is 60N?

Solution:

As we know,

F = μN

Given,

• N = 60N
• μ = 0.50

F = (0.5)(60)

F = 30 N

Hence the frictional force is 30 N

Example 2: What is the coefficient of friction if the frictional force exerted is 60N and the normal reaction offered is 80 N?

Solution:

As we know,

F = μN

Given,

• N = 80 N
• F = 60 N

μ = F/N

μ = 0.75

Hence, the coefficient of friction is 0.75

Example 3: What is the normal reaction if the frictional force exerted is 50N and the coefficient of friction is 0.25?

Solution:

As we know,

F = μN

Given,

• F = 50 N
• μ = 0.25

N = F/μ

N = 50/0.25

N = 200 N

Hence, the normal reaction offered is 200 N

Example 4: What is the gravitational force on two bodies of masses 2kg and 4kg respectively and the universal gravitational constant (G) being with the separation between them being 4 m?

Solution:

As we know,

F = G(m₁m₂)/r²

Putting the values from the question we get,

F = (6.6 × 10^-11 × 4 × 2)/4²

F = 3.3 × 10^-11 N

Example 5: What is the gravitational force on two bodies of masses 4 kg and 6 kg respectively and the universal gravitational constant (G) being with the separation between the two bodies being 2 m?

Solution:

As we know,

F = G(m₁m₂)/r²

Putting the values from the question we get,

F = (6.6 × 10^-11 × 4 × 6)/2²

F = 39.6 × 10^-11 N

Example 6: What is the electrostatic force between two charges of charge 4C and 5C which are at a distance of 4m with constant of proportionality 1?

Solution:

As we know,

F = K(q₁q₂)/r²

Putting the values from the question we get,

F = (1 × 4 × 5)/4²

F = 1.25 N

Example 7: What is the electrostatic force between two charges of charge (-3C) and (-6C) which are at a distance of 4 m with constant of proportionality 1?

Solution:

As we know,

F = K(q₁q₂)/r²

Putting the values from the question we get,

F = {1 × (-3) × (-6)}/4²

F = 1.125 N

Example 8: What is the magnetic force exerted by a charge of 3 C moving with a velocity of 6m/s in a magnetic field of 6 T and the value of sin θ = 1/2?

Solution:

Magnetic forces can be calculated by the following equation

F = qvBsinθ

Given,

• q= 3C
• B= 6 T
• sin θ = 1/2
• v= 6m/s

Putting the values we have,

F = 3 × 6 × 6 × 1/2

F = 54 N

Hence the magnetic force is 54 N

Example 9: What is the magnetic force exerted by a charge of 4C moving with a velocity of 8m/s in a magnetic field of 8T and the value of sin θ = 1?

Solution:

As we know,

Magnetic forces can be calculated by the following equation

F = qvBsinθ

Given,

• q = 4 C
• B = 8 T
• sin θ = 1
• v = 8 m/s

Putting the values we have,

F = 4 × 8 × 8 × 1

F = 256 N

Hence the magnetic force is 256 N

Forces are an external cause that makes a body move, stop, and increase its velocity and other. There are various types of forces in physics and they are generally classified into two categories that are, Contact Force and Non Contact Force.

In general, we define a push and pull as a force, and force is required for the proper working of the cosmos. There is a force between the fundamental particles and also between the galaxies. All these types of forces are caused by various reasons and in this article, we will learn about the types of forces, examples, and others. Before starting with the types of force we must first learn What is force. We have to study types of forces in class 8.