C++ Program to Illustrate the Order of Evaluation

C++




#include <iostream>
using namespace std;
  
int getValue() {
  return 42; 
}
  
int main()
{
    int a = 0;
    int b = a++ + getValue();
  
    cout << "a: " << a << endl;
    cout << "b: " << b << endl;
  
    return 0;
}


Output

a: 1
b: 42



Explanation

In the above example, we have an expression a++ + getValue(), first the value of a is used in the operation then the value of a is incremented and getValue() returns a value. The order of evaluation determines whether a++ or getValue() is evaluated first. In C++17, the order of evaluation is left-to-right, so a++ is evaluated before getValue().

Order of Evaluation in C++17

In C++ programming, the order of evaluation of expressions can have a significant impact on the behavior and correctness of the code. C++17 introduced changes to the order of evaluation rules, providing clearer guidelines and improving consistency across different compilers. In this article, we will explore the order of evaluation in C++17 and understand its implications.

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Example: C++ Program to Illustrate the Order of Evaluation

C++ #include using namespace std;    int getValue() {   return 42;  }    int main() {     int a = 0;     int b = a++ + getValue();        cout << "a: " << a << endl;     cout << "b: " << b << endl;        return 0; }...

Conclusion

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