Minimum number of consecutive sequences that can be formed in an array
Given an array of integers. The task is to find the minimum number of consecutive sequences that can be formed using the elements of the array.
Examples:
Input: arr[] = { -3, -2, -1, 0, 2 } Output: 2 Consecutive sequences are (-3, -2, -1, 0), (2). Input: arr[] = { 3, 4, 0, 2, 6, 5, 10 } Output: 3 Consecutive sequences are (0), {2, 3, 4, 5, 6} and {10}
Approach:
- Sort the array.
- Iterate the array, and check if current element is just 1 smaller than the next element.
- If it is then increment the count by 1.
- Return the final count of consecutive sequences.
Below is the implementation of above approach :
C++
// C++ program find the minimum number of consecutive // sequences in an array #include <bits/stdc++.h> using namespace std; int countSequences( int arr[], int n) { int count = 1; sort(arr, arr + n); for ( int i = 0; i < n - 1; i++) if (arr[i] + 1 != arr[i + 1]) count++; return count; } // Driver program int main() { int arr[] = { 1, 7, 3, 5, 10 }; int n = sizeof (arr) / sizeof (arr[0]); // function call to print required answer cout << countSequences(arr, n); return 0; } |
Java
// Java program find the minimum number of consecutive // sequences in an array import java.util.Arrays; import java.io.*; class GFG { static int countSequences( int arr[], int n) { int count = 1 ; Arrays.sort(arr); for ( int i = 0 ; i < n - 1 ; i++) if (arr[i] + 1 != arr[i + 1 ]) count++; return count; } // Driver program public static void main (String[] args) { int arr[] = { 1 , 7 , 3 , 5 , 10 }; int n = arr.length; // function call to print required answer System.out.println( countSequences(arr, n)); } //This code is contributed by ajit. } |
Python3
# Python3 program find the minimum number of consecutive # sequences in an array def countSequences(arr, n) : count = 1 arr.sort() for i in range ( n - 1 ) : if (arr[i] + 1 ! = arr[i + 1 ]) : count + = 1 return count # Driver program if __name__ = = "__main__" : arr = [ 1 , 7 , 3 , 5 , 10 ] n = len (arr) # function call to print required answer print (countSequences(arr, n)) # This code is contributed by Ryuga |
C#
// C# program find the minimum number of consecutive // sequences in an array using System; class GFG { static int countSequences( int []arr, int n) { int count = 1; Array.Sort(arr); for ( int i = 0; i < n - 1; i++) if (arr[i] + 1 != arr[i + 1]) count++; return count; } // Driver program static public void Main (String []args) { int []arr = { 1, 7, 3, 5, 10 }; int n = arr.Length; // function call to print required answer Console.WriteLine( countSequences(arr, n)); } } //This code is contributed by Arnab Kundu |
PHP
<?php // PHP program find the minimum number // of consecutive sequences in an array function countSequences( $arr , $n ) { $count = 1; sort( $arr ); for ( $i = 0; $i < $n - 1; $i ++) if ( $arr [ $i ] + 1 != $arr [ $i + 1]) $count ++; return $count ; } // Driver Code $arr = array ( 1, 7, 3, 5, 10 ); $n = count ( $arr ); // function call to print required answer echo countSequences( $arr , $n ); // This code is contributed by inder_verma ?> |
Javascript
<script> // Javascript program find the // minimum number of consecutive // sequences in an array function countSequences(arr, n) { let count = 1; arr.sort( function (a, b){ return a - b}); for (let i = 0; i < n - 1; i++) if (arr[i] + 1 != arr[i + 1]) count++; return count; } let arr = [ 1, 7, 3, 5, 10 ]; let n = arr.length; // function call to print required answer document.write(countSequences(arr, n)); </script> |
Output:
5
Time Complexity: O(n log n), where n is the size of the array.
Auxiliary Space: O(1)
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