Sum of Squares of n Natural Numbers Formula
Formulas for finding the sum of squares of n natural numbers, the sum of squares of first n even numbers, and the sum of squares of first n odd numbers are:
- Formula for Sum of squares of n natural numbers: [n(n+1)(2n+1)] / 6
- Formula for Sum of squares of first n even numbers: [2n(n + 1)(2n + 1)] / 3
- Formula for Sum of squares of first n odd numbers: [n(2n+1)(2n-1)] / 3
Sum of Squares Formula Table |
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Sum of Squares of First βnβ Natural Numbers | [n(n+1)(2n+1)] / 6 |
Sum of Squares of First βnβ Even Numbers | [2n(n + 1)(2n + 1)] / 3 |
Sum of Squares of First βnβ Odd Numbers | [n(2n+1)(2n-1)] / 3 |
Sum of Squares of n Natural numbers
Sum of Squares of n Natural numbers: The sum of squares of n natural numbers is calculated using the formula [n(n+1)(2n+1)] / 6 where βnβ is a natural number. There are formulas for calculating the sum of squares of first n even numbers as well as first n odd numbers.
In this article, we have covered the sum of squares of the βnβ natural number formula, its sum of squares proof, related examples, and others in detail.
Table of Content
- What is the Sum of Squares of βnβ Natural Numbers?
- Sum of Squares of n Natural Numbers Formula
- Sum of Squares of Natural Numbers Proof
- Sum of Squares of Even and Odd Natural Numbers
- Sum of Squares of Even Natural Numbers
- Sum of Squares of Odd Natural Numbers
- Sum of Squares of Two and Three Natural Numbers
- Sum of Squares in Geometry
- Sum of Squares of n Natural Numbers Solved Questions
- Practice Questions on Sum of Squares of n Natural Numbers
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