Solved Examples on Parallelogram

We have solved some select questions on parallelogram down below. They will help you better improve your understanding of the concepts in this chapter.

Example 1: Find the length of the other side of a parallelogram with a base of 12 cm and a perimeter of 60 cm.

Solution:

Given perimeter of a parallelogram = 60cm.

Base length of given parallelogram = 12 cm. 

P = 2 (a + b) units 

Where b = 12cm and P = 40cm.

60 = 2 (a + 12)

60 = 2a + 24

2a = 60-24

2a = 36

a = 18cm

Therefore, the length of the other side of the parallelogram is 18 cm. 

Example 2: Find the perimeter of a parallelogram with the base and side lengths of 15cm and 5cm, respectively.

Solution:

Base length of given parallelogram = 15 cm

Side length of given parallelogram = 5 cm

Perimeter of a parallelogram is given by,

P = 2(a + b) units.

Putting the values, we get

P = 2(15 + 5)

P = 2(20)

P = 40 cm

Therefore, the perimeter of a parallelogram will be 40 cm.

Example 3: The angle between two sides of a parallelogram is 90°. If the lengths of two parallel sides are 5 cm and 4 cm, respectively, find the area.

Solution:

If one angle of the parallelogram is 90°. Then, the rest of the angles are also 90°. Therefore, the parallelogram becomes a rectangle. The area of the rectangle is length times breadth.

Area of parallelogram = 5 × 4

Area of parallelogram = 20cm²

Example 4: Find the area of a parallelogram when the diagonals are given as 8 cm, and 10 cm, the angle between the diagonals is 60°.

Solution:

In order to find the area of the parallelogram, the base and height should be known, lets’s first find the base of the parallelogram, applying the law of cosines,

b² = 4² + 5² – 2(5)(4)cos(120°)

b² = 16 + 25 – 40(0.8)

b² = 9

b = 3cm 

Finding the height of the parallelogram,

4/sinθ = b/sin120

4/sinθ = 3/-0.58

sinθ = -0.773

θ = 50°

Now, to find the height,

Sinθ = h/10

0.76 = h/10

h = 7.6cm

Area of the parallelogram = 1/2 × 3 × 7.6
                                         = 11.4 cm²

Example 5: Prove that a parallelogram circumscribing a circle is a rhombus.

Solution:

Given: 

• Parallelogram ABCD
• Circle PQRS

To prove: ABCD is a rhombus.

Proof:

We know that the tangents drawn from an exterior point to a circle are equal to each other. Therefore:

AP = AS ⇢ (1)

BP = BQ ⇢ (2)

DS = DR ⇢ (3)

CR = CQ ⇢ (4)

Adding the LHS and RHS of equations 1, 2, 3, and 4:

AP + BP + DS + CR = AS + BQ + DR + CQ

AB + DR + CR = AS + DS + BC

AB + CD = AD + BC

Since the opposite angles of a parallelogram are equal:

2AB = 2BC

AB = BC, and similarly, CD = AD.

Therefore: AB = CD = BC = AD.

Since all the sides are equal, ABCD is a rhombus.

Parallelogram is a two-dimensional geometrical shape whose opposite sides are equal in length and parallel. The opposite angles of a parallelogram are equal in measure.

In this article, we will learn about the definition of a parallelogram, its properties, types, theorem and formulas on the area and perimeter of a parallelogram in detail.