Solved Example on Chemical Kinetics
Let’s solve some example problems on Chemical Kinetics
Example 1 : Identify the reaction order from each of the following rate constants.
- k = 2.3 × 10-5 L mol-1 s-1
- k = 3 × 10-4 s-1
Solution:
(1) The unit of second order rate constant is L mol-1 s-1 ,therefore k = 2.3 × 10-5 L mol-1 s-1 represents a second order reaction.
(2) The unit of a first-order rate constant is s-1 therefore k = 3 × 10-4 s-1 represents a first-order reaction.
Example 2: A first-order reaction is found to have a rate constant, k = 5.5 × 10-14 s-1. Find the half-life of the reaction.
Solution:
The half-life for a first-order reaction is t1/2 =0.693/k
So here, t1/2 = 0.693/ (5.5 × 10-14 )s-1 = 1.26 × 1013s
Example 3: Calculate the overall order of a reaction which has the rate expression
- Rate = k [A]1/2 [B]3/2
- Rate = k [A]3/2 [B]-1
Solution:
Rate = k [A]x[B]y
Order = x + y
1. Order = 1/2 + 3/2 = 2, i.e., hence the reaction is of second order
2. Order = 3/2 + (–1) = 1/2, i.e., hence the reaction is of half order.
Chemical Kinetics
Chemical Kinetics is a part of physical chemistry that focuses on the rate of chemical reactions and the reasons behind them. It involves figuring out the speed and details of chemical reactions, studying the factors that affect how fast they happen, and how molecules interact during these changes.
This field is important in various scientific areas, from improving industrial processes to understanding complicated reactions in biological systems. By focusing on how molecules interact, chemical kinetics helps us to understand the complex movements of atoms and molecules in the world of chemistry.
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