Separate alphabets and numbers from a string using findall
In Python, we should import the regex library to use regular expressions. The pattern [0-9]+ is used to match the numbers in the string. Whereas ‘[a-zA-Z]’ is used to find all alphabets from the given string. We use the findall(Pattern, String) method that returns a list of all non-overlapping matches of the given pattern or regular expression in a string.
Python3
import re# Function to separate the numbers # and alphabets from the given stringdef separateNumbersAlphabets(str): numbers = re.findall(r'[0-9]+', str) alphabets = re.findall(r'[a-zA-Z]+', str) print(*numbers) print(*alphabets)# Driver codestr = "adbv345hj43hvb42"separateNumbersAlphabets(str) |
Output:
345 43 42
adbv hj hvb
Time complexity: O(n), where n is the length of the input string.
Auxiliary space: O(d + a), where n is the length of the input string, d is the number of digits, and a is the number of alphabets in the input string.
Python program to separate alphabets and numbers in a string
Given a string containing numbers and alphabets, the task is to write a Python program to separate alphabets and numbers from a string using regular expression.
Examples
Input: abcd11gdf15hnnn678hh4
Output: 11 15 678 4abcd gdf hnnn hh
Explanation: The string is traversed from left to right and number and alphabets are separated from the given string .
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