Home Python Naive Approach checking each word in the string

Naive Approach checking each word in the string

Using list comprehension to check if string contains element from list

Here we are splitting the string into list of words and then matching each word of this list with the already present list of words we want to check.

Python3




# initializing string
test_string = "There are 2 apples for 4 persons"
 
# initializing test list
test_list = ['apples', 'oranges']
 
# printing original string
print("The original string : " + test_string)
 
# printing original list
print("The original list : " + str(test_list))
 
test_string=test_string.split(" ")
 
flag=0
for i in test_string:
    for j in test_list:
        if i==j:
            flag=1
            break
if flag==1:
    print("String contains the list element")
else:
    print("String does not contains the list element")
 






                        









																																						

																								

																										
Output


The original string : There are 2 apples for 4 persons
The original list : ['apples', 'oranges']
String contains the list element




																																						

																							

											
											

												
Python | Test if string contains element from list

																								

																										
We are given a String and our task is to test if the string contains elements from the list.

																																						

																								

																										
Example:

																																						

																								

																										
Input:    String: Geeks for Geeks is one of the best company.
        List: ['Geeks', 'for']

Output:    Does string contain any list element : True

																																						

																							

										


										
										

											
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