Find the smallest element in list comparing every element
Python3
# Python program to find smallest # number in a listl=[ int(l) for l in input("List:").split(",")]print("The list is ",l)# Assign first element as a minimum.min1 = l[0]for i in range(len(l)): # If the other element is min than first element if l[i] < min1: min1 = l[i] #It will changeprint("The smallest element in the list is ",min1) |
Input:
List: 23,-1,45,22.6,78,100,-5
Output:
The list is ['23', '-1', '45', '22.6', '78', '100','-5'] The smallest element in the list is -5
Python program to find smallest number in a list
We are given a list of numbers and our task is to write a Python program to find the smallest number in given list. For the following program we can use various methods including the built-in min method, sorting the array and returning the last element, etc.
Example:
Input : list1 = [10, 20, 4] Output : 4 Input : list2 = [20, 10, 20, 1, 100] Output : 1
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