Checking for Interface Implementation
You can write a function to check if an object or class implements a specific interface. This function can iterate through the method names defined in the interface and verify their presence in the object or class.
Example: This example shows the implementation of a interface in JavaScript.
Javascript
const MyInterface = { method1: function () { }, method2: function (param1, param2) { }, }; class MyClass { method1() { console.log( "Method 1 called" ); } method2(param1, param2) { console.log( `Method 2 called with ${param1} and ${param2}`); } } function implementsInterface(obj, interfaceObj) { for (const method in interfaceObj) { if (!(method in obj) || typeof obj[method] !== "function" ) { return false ; } } return true ; } const myObject = new MyClass(); if (implementsInterface(myObject, MyInterface)) { console.log( "myObject implements MyInterface" ); } else { console.log( "myObject does not implement MyInterface" ); } |
Output
myObject implements MyInterface
Implementing Interfaces in JavaScript
In JavaScript, there is no built-in concept of interfaces like you might find in languages like Java or C#. However, you can achieve similar functionality by defining and implementing your own interfaces using objects and classes. In this explanation, this article will guide you through the process of implementing interfaces in JavaScript.
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