How to usefilter() and some() in Javascript

  • The some() method is used to check if there is any object in array1 with the same id as the current object in array2.
  • The filter() method is applied to array2 to only include objects that are not present in array1 (based on the id property).
  • The final array, resultArray, contains unique objects from both arrays.

Example: This example shows the implementation of the above-explained approach.

JavaScript




const array1 = [{ id: 1, name: 'John' },
{ id: 2, name: 'Jane' }];
const array2 = [{ id: 2, name: 'Jane' },
{ id: 3, name: 'Doe' }];
 
const mergedArray = array2.filter(item2 =>
    !array1.some(item1 => item1.id === item2.id)
);
const resultArray = [...array1, ...mergedArray];
console.log(resultArray);


Output

[
  { id: 1, name: 'John' },
  { id: 2, name: 'Jane' },
  { id: 3, name: 'Doe' }
]

How to Merge two Different Arrays of Objects with Unique Values only in JavaScript ?

Merging two arrays of objects with unique values is a common task in JavaScript. This operation involves combining the elements of two arrays while ensuring that each resulting object has a unique identifier. We will explore various approaches to merging two arrays of objects with unique values.

These are the following approaches:

Table of Content

  • Using concat() and filter()
  • Using reduce()
  • Using Map and Set
  • Using filter() and some()
  • Using filter() and Map and has()

Similar Reads

Approach 1: Using concat() and filter()

The concat() method is used to merge array1 and the filtered values from array2 to create a new array. The filter() method is applied to array2, ensuring that only objects not present in array1 (based on the id property) are included. The resulting array, mergedArray, contains unique objects from both arrays....

Approach 2: Using reduce()

...

Approach 3: Using Map and Set

The reduce() function is used to iteratively merge array2 into array1. The some() method is employed to check if an object with the same id already exists in the accumulated array. If the id is not found, the object is pushed to the accumulator, resulting in a merged array with unique objects....

Approach 4: Using filter() and some()

...

Approach 5: Using filter() and Map and has()

A Map is used to store the unique objects based on their id properties. The Set is employed to ensure uniqueness, preventing duplicate objects with the same id. Finally, Array.from() is used to convert the values of the Map back into an array....

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