Application of Gauss Law FAQs

What is Gauss Law?

According to the Gauss law, the total flux linked with a closed surface is 1/ε0 times the charge enclosed by the closed surface....

Applications of Gauss Law

We’ll look at a few of the applications of Gauss law in this article. To begin with, we know that in some situations, calculating the electric field is fairly difficult and requires a lot of integration. Gauss’s Law is used to make calculating the electric field easier....

Electric Field due to Infinite Wire

Consider a wire that is infinitely long and has a linear charge density λ. To compute the electric field, we utilize a cylindrical Gaussian surface. The flux through the end of the surface will be 0 since the electric field E is radial. Because the electric field and the area vector are perpendicular to each other, this is the case. We may argue that the electric field’s magnitude will be constant since it is perpendicular to every point on the curved surface....

Electric Field due to Infinite Plane Sheet

Consider an infinite plane sheet with a cross-sectional area A and a surface charge density σ. The infinite plane sheet is in the following position:...

Electric Field due to Thin Spherical Shell

Consider a thin spherical shell with a radius “R”, charge q, and a surface charge density of σ (such that σ = q / 4 π r2). The shell possesses spherical symmetry. The electric field owing to the spherical shell can be calculated in two ways:...

Electric Field Outside the Spherical Shell

Take a point P outside the spherical shell at a distance r from the center of the spherical shell to get the electric field. We use a Gaussian spherical surface with a radius of r and center ‘O’. Because all points are equally spaced “r” from the sphere’s center, the Gaussian surface will pass through P and experience a constant electric field E all around. So, Therefore, the total electric flux:...

Electric Field Inside the Spherical Shell

Let’s look at point P inside the spherical shell to see how the electric field there is. We may use symmetry to create a spherical Gaussian surface that passes through P, is centered at O, and has a radius of r. Now, based on Gauss’s Law,...

Examples on Application of Gauss Law

Example 1: A hemispherical bowl of radius r is placed in a region of space with a uniform electric field E. Find out the electric flux through the bowl....

Application of Gauss Law FAQs

What is Gauss Law?...