Sum of the count of number of adjacent squares in an M X N grid
Given an M × N matrix. The task is to count the number of adjacent cells and calculate their sum.
Two cells are said to be connected if they are adjacent to each other horizontally, vertically, or diagonally.
Examples :
Input : m = 2, n = 2
Output : 12
Input : m = 3, n = 2
Output: 22
See the below diagram where numbers written on it denotes number of adjacent squares.
Approach:
In a m X n grid there can be 3 cases:
- Corner cells touch 3 cells, and there are always 4 corner cells.
- Edge cells touch 5 cells, and there are always 2 * (m+n-4) edge cells.
- Interior cells touch 8 cells, and there are always (m-2) * (n-2) interior cells.
Therefore,
Sum = 3*4 + 5*2*(m+n-4) + 8*(m-2)*(n-2) = 8mn - 6m - 6n +4
Below is the implementation of the above approach:
C++
// C++ implementation of the above approach #include <bits/stdc++.h> using namespace std; // function to calculate the sum of all cells adjacent value int sum( int m, int n) { return 8 * m * n - 6 * m - 6 * n + 4; } // Driver program to test above int main() { int m = 3, n = 2; cout << sum(m, n); return 0; } |
Java
// Java implementation of the above approach class GFG { // function to calculate the sum // of all cells adjacent value static int sum( int m, int n) { return 8 * m * n - 6 * m - 6 * n + 4 ; } // Driver Code public static void main (String[] args) { int m = 3 , n = 2 ; System.out.println(sum(m, n)); } } // This Code is contributed by AnkitRai01 |
Python3
# Python3 implementation of the above approach # function to calculate the sum # of all cells adjacent value def summ(m, n): return 8 * m * n - 6 * m - 6 * n + 4 # Driver Code m = 3 n = 2 print (summ(m, n)) # This code is contributed by Mohit Kumar |
C#
// C# implementation of the above approach using System; class GFG { // function to calculate the sum // of all cells adjacent value static int sum( int m, int n) { return 8 * m * n - 6 * m - 6 * n + 4; } // Driver Code public static void Main (String []args) { int m = 3, n = 2; Console.WriteLine(sum(m, n)); } } // This code is contributed by andrew1234 |
Javascript
<script> // Javascript implementation of the above approach // function to calculate the sum of all cells adjacent value function sum(m, n) { return 8 * m * n - 6 * m - 6 * n + 4; } // Driver program to test above var m = 3, n = 2; document.write(sum(m, n)); </script> |
Output:
22
Time Complexity:
Auxiliary Space: O(1)
Contact Us