remainder() in C++
This function is also used to return the remainder(modulus) of 2 floating point numbers mentioned in its arguments.The quotient computed is rounded.
remainder = number – rquot * denom
Where rquot is the result of: number/denom, rounded toward the nearest integral value (with halfway cases rounded toward the even number).
Syntax :
double remainder(double a, double b) float remainder(float a, float b) long double remainder(long double a, long double b) Parameter: a and b are the values of numerator and denominator. Return: The remainder() function returns the floating point remainder of numerator/denominator rounded to nearest.
Time Complexity: O(1)
Space Complexity: O(1)
Error or Exception : It is mandatory to give both the arguments otherwise it will give error – no matching function for call to ‘remainder()’ like this.
# CODE 1
CPP
// CPP program to demonstrate // remainder() function #include <cmath> #include <iostream> using namespace std; int main() { double a, b; double answer; a = 50.35; b = -4.1; // here quotient is -12.2805 and rounded to nearest value then // rquot = -12. // remainder = 50.35 – (-12 * -4.1) answer = remainder(a, b); cout << "Remainder of " << a << "/" << b << " is " << answer << endl; a = 16.80; b = 3.5; // here quotient is 4.8 and rounded to nearest value then // rquot = -5. // remainder = 16.80 – (5 * 3.5) answer = remainder(a, b); cout << "Remainder of " << a << "/" << b << " is " << answer << endl; a = 16.80; b = 0; answer = remainder(a, b); cout << "Remainder of " << a << "/" << b << " is " << answer << endl; return 0; } |
OUTPUT :
Remainder of 50.35/-4.1 is 1.15 Remainder of 16.8/3.5 is -0.7 Remainder of 16.8/0 is -nan
# CODE 2
CPP
// CPP program to demonstrate // remainder() function #include <cmath> #include <iostream> using namespace std; int main() { int a = 50; double b = 41.35, answer; answer = remainder(a, b); cout << "Remainder of " << a << "/" << b << " = " << answer << endl; return 0; } |
OUTPUT :
Remainder of 50/41.35 = 8.65
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