Program to check whether the given number is Buzz Number or not
A number is said to be Buzz Number if it ends with 7 OR is divisible by 7.
The task is to check whether the given number is buzz number or not.
Examples:
Input : 63 Output : Buzz Number Explanation: 63 is divisible by 7, one of the condition is satisfied. Input : 72 Output : Not a Buzz Number Explanation: 72 % 7 != 0, 72 is neither divisible by 7 nor it ends with 7 so it is not a Buzz Number.
C++
// C++ program to check whether the // given number is Buzz Number or not. #include <cmath> #include <iostream> using namespace std; // function to check BUzz number. bool isBuzz( int num) { // checking if the number // ends with 7 and is divisible by 7 return (num % 10 == 7 || num % 7 == 0); } // Driver method int main( void ) { int i = 67, j = 19; if (isBuzz(i)) cout << "Buzz Number\n" ; else cout << "Not a Buzz Number\n" ; if (isBuzz(j)) cout << "Buzz Number\n" ; else cout << "Not a Buzz Number\n" ; } |
Java
// Java program to check whether the // given number is Buzz number or not import java.io.*; import java.util.*; class GFG { // function to check BUzz number. static boolean isBuzz( int num) { // checking if the number // ends with 7 and is divisible by 7 return (num % 10 == 7 || num % 7 == 0 ); } // Driver method public static void main(String args[]) { int i = 67 , j = 19 ; if (isBuzz(i)) System.out.println( "Buzz Number" ); else System.out.println( "Not a Buzz Number" ); if (isBuzz(j)) System.out.println( "Buzz Number" ); else System.out.println( "Not a Buzz Number" ); } } // This code is contributed by Nikita Tiwari. |
Python3
# Python program to check whether the # given number is Buzz Number or not. # function to check BUzz number. def isBuzz(num) : # checking if the number # ends with 7 and is divisible by 7 return (num % 10 = = 7 or num % 7 = = 0 ) # Driver method i = 67 j = 19 if (isBuzz(i)) : print ( "Buzz Number" ) else : print ( "Not a Buzz Number" ) if (isBuzz(j)) : print ( "Buzz Number" ) else : print ( "Not a Buzz Number" ) |
PHP
<?php // PHP code to check Buzz Number // Function for Buzz Number function isBuzz( $num ) { // checking if the number // ends with 7 and is divisible by 7 return ( $num % 10 == 7 || $num % 7 == 0); } // Driver Code $i = 67; $j = 43; if (isBuzz( $i )) print ( "Buzz Number\n" ); else print ( "Not Buzz Number\n" ); if (isBuzz( $j )) print ( "Buzz Number\n" ); else print ( "Not Buzz Number\n" ); // This code is contributed by akash7981 ?> |
C#
// C# program to check whether the // given number is Buzz number or not using System; class GFG { // function to check BUzz number. static bool isBuzz( int num) { // checking if the number // ends with 7 and is // divisible by 7 return (num % 10 == 7 || num % 7 == 0); } // Driver method public static void Main() { int i = 67, j = 19; if (isBuzz(i)) Console.WriteLine( "Buzz Number" ); else Console.Write( "Not a Buzz Number" ); if (isBuzz(j)) Console.Write( "Buzz Number" ); else Console.Write( "Not a Buzz Number" ); } } // This code is contributed by Nitin mittal. |
Javascript
<script> // javascript program to check whether the // given number is Buzz number or not // function to check BUzz number. function isBuzz(num) { // checking if the number // ends with 7 and is divisible by 7 return (num % 10 == 7 || num % 7 == 0); } // Driver method var i = 67, j = 19; if (isBuzz(i)) document.write( "Buzz Number<br>" ); else document.write( "Not a Buzz Number<br>" ); if (isBuzz(j)) document.write( "Buzz Number<br>" ); else document.write( "Not a Buzz Number<br>" ); // This code is contributed by Princi Singh </script> |
Output:
Buzz Number Not a Buzz Number
Time complexity : O(1) as there are atomic statements and no loops.
Auxiliary Space: O(1)
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