Print the pattern by using one loop | Set 2 (Using Continue Statement)
Given a number n, print triangular pattern. We are allowed to use only one loop.
Example:
Input: 7 Output: * * * * * * * * * * * * * * * * * * * * * * * * * * * *
We use single for-loop and in the loop we maintain two variables for line count and current star count. If current star count is less than current line count, we print a star and continue. Else we print a new line and increment line count.
C++
// C++ program to print a pattern using single // loop and continue statement #include<bits/stdc++.h> using namespace std; // printPattern function to print pattern void printPattern( int n) { // Variable initialization int line_no = 1; // Line count // Loop to print desired pattern int curr_star = 0; for ( int line_no = 1; line_no <= n; ) { // If current star count is less than // current line number if (curr_star < line_no) { cout << "* " ; curr_star++; continue ; } // Else time to print a new line if (curr_star == line_no) { cout << "\n" ; line_no++; curr_star = 0; } } } // Driver code int main() { printPattern(7); return 0; } |
Java
// Java program to print a pattern using single // loop and continue statement import java.io.*; class GFG { // printPattern function to print pattern static void printPattern( int n) { // Variable initialization // Line count int line_no = 1 ; // Loop to print desired pattern int curr_star = 0 ; for ( line_no = 1 ; line_no <= n;) { // If current star count is less than // current line number if (curr_star < line_no) { System.out.print ( "* " ); curr_star++; continue ; } // Else time to print a new line if (curr_star == line_no) { System.out.println ( "" ); line_no++; curr_star = 0 ; } } } // Driver code public static void main (String[] args) { printPattern( 7 ); } } // This code is contributed by vt_m |
Python 3
# Python 3 program to print # a pattern using single # loop and continue statement # printPattern function # to print pattern def printPattern(n): # Variable initialization line_no = 1 # Line count # Loop to print # desired pattern curr_star = 0 line_no = 1 while (line_no < = n ): # If current star count # is less than current # line number if (curr_star < line_no): print ( "* " , end = "") curr_star + = 1 continue # Else time to print # a new line if (curr_star = = line_no): print ("") line_no + = 1 curr_star = 0 # Driver code printPattern( 7 ) # This code is contributed # by Smitha |
C#
// C# program to print a pattern using single // loop and continue statement using System; class GFG { // printPattern function to print pattern static void printPattern( int n) { // Variable initialization // Line count int line_no = 1; // Loop to print desired pattern int curr_star = 0; for ( line_no = 1; line_no <= n;) { // If current star count is less than // current line number if (curr_star < line_no) { Console.Write ( "* " ); curr_star++; continue ; } // Else time to print a new line if (curr_star == line_no) { Console.WriteLine (); line_no++; curr_star = 0; } } } // Driver code public static void Main () { printPattern(7); } } // This code is contributed by vt_m |
PHP
<?php // php program to print a // pattern using single loop // and continue statement // printPattern function // to print pattern function printPattern( $n ) { // Variable initialization $line_no = 1; // Line count // Loop to print desired pattern $curr_star = 0; for ( $line_no = 1; $line_no <= $n ? { // If current star count is less // than current line number if ( $curr_star < $line_no ) { echo "* " ; $curr_star ++; continue ; } // Else time to print // a new line if ( $curr_star == $line_no ) { echo "\n" ; $line_no ++; $curr_star = 0; } } } // Driver code $n =7; printPattern( $n ); // This code is contributed by mits ?> |
Javascript
<script> // JavaScript program to print a pattern using single // loop and continue statement // printPattern function to print pattern function printPattern(n) { // Variable initialization var line_no = 1; // Line count // Loop to print desired pattern var curr_star = 0; for ( var line_no = 1; line_no <= n; ) { // If current star count is less than // current line number if (curr_star < line_no) { document.write( "* " ); curr_star++; continue ; } // Else time to print a new line if (curr_star == line_no) { document.write( "<br>" ); line_no++; curr_star = 0; } } } // Driver code printPattern(7); // This code is contributed by rdtank. </script> |
Output:
* * * * * * * * * * * * * * * * * * * * * * * * * * * *
Time Complexity: O(n2)
Auxiliary Space: O(1)
Please refer below post for one more approach.
Print pattern using only one loop
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