Percentage increase in the volume of cuboid if length, breadth and height are increased by fixed percentages
Given a cuboid and three integers L, B, and H. If the length of the cuboid is increased by L%, breadth is increased by B% percent, and height is increased by H% percent. The task is to find the percentage increase in the volume of the cuboid.
Examples:
Input: L = 50, B = 20, H = 10
Output: 98%
Input: L = 10, B = 20, H = 30
Output: 71.6%
Approach: Suppose the original length, breadth and height of the cuboid be l, b and h respectively. Now, the increased length will be (l + ((L * l) / 100)) i.e. increasedLength = l * (1 + (L / 100)). Similarly, increased breadth and height will be increasedBreadth = b * (1 + (B / 100)) and increasedHeight = h * (1 + (H / 100)).
Now, calculate originalVol = l * b * h and increasedVol = increasedLength * increasedBreadth * increasedHeight.
And, the percentage increase can be found as ((increasedVol – originalVol) / originalVol) * 100
(((l * (1 + (L / 100)) * b * (1 + (B / 100)) h * (1 + (H / 100))) – (l * b * h)) / (l * b * h)) * 100
((l * b * h * (((1 + (L / 100)) * (1 + (B / 100)) * (H / 100)) – 1)) / (l * b * h)) * 100
(((1 + (L / 100)) * (1 + (B / 100)) * (1 + (H / 100))) – 1) * 100
Below is the implementation of the above approach:
C++
// C++ implementation of the approach #include <bits/stdc++.h> using namespace std; // Function to return the percentage increase // in the volume of the cuboid double increaseInVol( double l, double b, double h) { double percentInc = (1 + (l / 100)) * (1 + (b / 100)) * (1 + (h / 100)); percentInc -= 1; percentInc *= 100; return percentInc; } // Driver code int main() { double l = 50, b = 20, h = 10; cout << increaseInVol(l, b, h) << "%" ; return 0; } |
Java
// Java implementation of the approach class GFG { // Function to return the percentage increase // in the volume of the cuboid static double increaseInVol( double l, double b, double h) { double percentInc = ( 1 + (l / 100 )) * ( 1 + (b / 100 )) * ( 1 + (h / 100 )); percentInc -= 1 ; percentInc *= 100 ; return percentInc; } // Driver code public static void main(String[] args) { double l = 50 , b = 20 , h = 10 ; System.out.println(increaseInVol(l, b, h) + "%" ); } } // This code is contributed by Code_Mech |
Python3
# Python3 implementation of the approach # Function to return the percentage increase # in the volume of the cuboid def increaseInVol(l, b, h): percentInc = (( 1 + (l / 100 )) * ( 1 + (b / 100 )) * ( 1 + (h / 100 ))) percentInc - = 1 percentInc * = 100 return percentInc # Driver code l = 50 b = 20 h = 10 print (increaseInVol(l, b, h), "%" ) # This code is contributed by Mohit Kumar |
C#
// C# implementation of the approach using System; class GFG { // Function to return the percentage increase // in the volume of the cuboid static double increaseInVol( double l, double b, double h) { double percentInc = (1 + (l / 100)) * (1 + (b / 100)) * (1 + (h / 100)); percentInc -= 1; percentInc *= 100; return percentInc; } // Driver code public static void Main() { double l = 50, b = 20, h = 10; Console.WriteLine(increaseInVol(l, b, h) + "%" ); } } // This code is contributed by Code_Mech |
Javascript
<script> // Javascript implementation of the approach // Function to return the percentage increase // in the volume of the cuboid function increaseInVol(l, b, h) { let percentInc = (1 + (l / 100)) * (1 + (b / 100)) * (1 + (h / 100)); percentInc -= 1; percentInc *= 100; return percentInc; } // Driver code let l = 50, b = 20, h = 10; document.write(increaseInVol(l, b, h) + "%" ); </script> |
98%
Time Complexity: O(1)
Auxiliary Space: O(1)
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