Output of the Program | Use Macros Carefully!
Predict the output of the below program
C++
#include <iostream> using namespace std; #define square(x) x*x int main() { int x; x = 36 / square(6); cout << x; return 0; } // This code is contributed by sarajadhav12052009 |
C
#include <stdio.h> #define square(x) x*x int main() { int x; x = 36/square(6); printf ( "%d" ,x); getchar (); return 0; } |
Output
36
Explanation: Preprocessor replaces square(6) by 6*6 and the expression becomes x = 36/6*6 and value of x is calculated as 36. If we want correct behavior from macro square(x), we should declare it as #define square(x) ((x)*(x)) /* Note that the expression (x*x) will also fail for square(6-2) */
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