NPDA for accepting the language L = {am bn cp dq | m+n=p+q ; m,n,p,q>=1}

Problem –
L = {abcd, abbcdd, abbccd, abbbccdd, ......}
Explanation –
 = { 1, z } 
Approach used in the construction of PDA –
Stack transition functions –
(q0, a, z)  (q0, 1z)
(q0, a, 1)  (q0, 11)
(q0, b, 1)  (q1, 11)
(q1, b, 1)  (q1, 11)
(q1, c, 1)  (q2, )
(q2, c, 1)  (q2, )
(q2, d, 1)  (q3, )
(q3, d, 1)  (q3, )
(q3, , z)  (qf, z)     
        


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