NPDA for accepting the language L = {am bn cp dq | m+n=p+q ; m,n,p,q>=1}
Problem –
L = {abcd, abbcdd, abbccd, abbbccdd, ......}
Explanation –
= { 1, z }
Approach used in the construction of PDA –
Stack transition functions –
(q0, a, z) (q0, 1z) (q0, a, 1) (q0, 11) (q0, b, 1) (q1, 11) (q1, b, 1) (q1, 11) (q1, c, 1) (q2, ) (q2, c, 1) (q2, ) (q2, d, 1) (q3, ) (q3, d, 1) (q3, ) (q3, , z) (qf, z)
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