Mathematics | Probability Distributions Set 5 (Poisson Distribution)

Introduction –

Expected Value –

Variance and Standard Deviation –

Relation with Exponential Distribution –

• Example- For the case of the thin copper wire, suppose that the number of flaws follows a Poisson distribution with a mean of 2.3 flaws per millimeter. Determine the probability of exactly two flaws in 2 millimeter of wire.
• Solution- Let X denote the number of flaws in 1 millimeter of wire. The first step we need to do is to find the parameter which is nothing but the Expected value of the random variable. In this case we are given the Expected number of flaws in 1 millimeter of wire. We need to find the Expected number of flaws in 2 millimeter of wire. Expected number of flaws in 2 millimeter of wire = 2*np = = 2*2.3 = 4.6 Therefore,

GATE CS Corner Questions

References-