LinkedList element() method in Java with Examples
The element() method of java.util.LinkedList class retrieves, but does not remove, the head (first element) of this list.
Syntax:
public E element()
Return Value: This method returns the head of this list.
Below are the examples to illustrate the element() method
Example 1:
// Java program to demonstrate // element() method // for Integer value import java.util.*; public class GFG1 { public static void main(String[] argv) throws Exception { try { // creating object of LinkedList<Integer> LinkedList<Integer> list = new LinkedList<Integer>(); // add some elements to list list.add( 10 ); list.add( 20 ); list.add( 30 ); // print the linked list System.out.println( "LinkedList : " + list); // getting the head of list // using element() method int value = list.element(); // print the head of list System.out.println( "Head of list : " + value); } catch (NullPointerException e) { System.out.println( "Exception thrown : " + e); } } } |
Output:
LinkedList : [10, 20, 30] Head of list : 10
Example 2:
// Java program to demonstrate // element() method // for String value import java.util.*; public class GFG1 { public static void main(String[] argv) throws Exception { try { // creating object of LinkedList<String> LinkedList<String> list = new LinkedList<String>(); // add some elements to list list.add( "A" ); list.add( "B" ); list.add( "C" ); // print the linked list System.out.println( "LinkedList : " + list); // getting the head of list // using element() method String value = list.element(); // print the head of list System.out.println( "Head of list : " + value); } catch (NullPointerException e) { System.out.println( "Exception thrown : " + e); } } } |
Output:
LinkedList : [A, B, C] Head of list : A
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