Derivation of 2CosaSinb Formula
We can derive the 2cosasinb formula with the help of the sum and difference of formulae of the sine function.
- sin (A + B) = sin A cos B + cos A sin B… (1)
- sin (A – B) = sin A cos B – cos A sin B…(2)
Now subtract the equation (2) from the equation (1)
⇒ sin (A + B) – sin (A – B) = (sin A cos B + cos A sin B) – (sin A cos B – cos A sin B)
⇒ sin (A + B) – sin (A – B) = sin A cos B + cos A sin B – sin A cos B + cos A sin B
⇒ sin (A + B) – sin (A – B) = cos A sin B + cos A sin B
⇒ sin (A + B) – sin (A – B) = 2 cos A sin B
Hence, 2 cos A sin B = sin (A + B) – sin (A – B)
Articles Related to 2cosAsinB Formula:
2cosAsinB Formula
2cosasinb is one of the important trigonometric formulas which is equal to sin (a + b) – sin (a-b). 2cosAsinB Formula is used in trigonometry to solve various equations and problems more efficiently. This formula is found using the sum and difference of the sine function.
In this article, we have covered, in brief, trigonometric ratios, 2Cos(a)Sin(b) Formula, its derivation and others in detail.
Table of Content
- Trigonometric Ratios
- 2Cos(a)Sin(b) Formula
- Derivation of 2CosaSinb Formula
- Examples on 2CosaSinb Formula
- FAQs on 2cosAsinB
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