Java Math incrementExact(int x) method
The java.lang.Math.incrementExact() is a built-in math function in java which returns the argument incremented by one.It throws an exception if the result overflows an int.As incrementExact(int x) is static, so object creation is not required.
Syntax :
public static int incrementExact(int x) Parameter : x : the value to be incremented Return : This method returns the argument incremented by one. Exception : It throws ArithmeticException - if the result overflows an int
Example : To show working of java.lang.Math.incrementExact() method.
// Java program to demonstrate working // of java.lang.Math.incrementExact() method import java.lang.Math; class Gfg1 { // driver code public static void main(String args[]) { int a = 0 ; for ( int i = 0 ; i < 5 ; i++) { a = Math.incrementExact(a); System.out.println(a); } } } |
Output:
1 2 3 4 5
// Java program to demonstrate working // of java.lang.Math.incrementExact() method import java.lang.Math; class Gfg2 { // driver code public static void main(String args[]) { int x = Integer.MAX_VALUE; System.out.println(Math.incrementExact(x)); } } |
Output:
Runtime Error : Exception in thread "main" java.lang.ArithmeticException: integer overflow at java.lang.Math.incrementExact(Math.java:909) at Gfg2.main(File.java:13)
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