Decrypt a string according to given rules
Given encrypted string str, the task is to decrypt the given string when the encryption rules are as follows:
- Start with the first character of the original string.
- In every odd step, append the next character to it.
- In every even step, prepend the next character to the encrypted string so far.
For example, if str = “Beginner” then the encrypted string will be,
g -> ge -> ege -> egek -> segek
Examples:
Input: str = “segosegekfrek”
Output: w3wikiInput: str = “vrstie”
Output: strive
Approach: The steps that are given to encrypt the string can be followed in reverse order to obtain the original string. There will be two conditions to obtain the original string:
- If the string is of odd length, in the odd step add the characters from the back in the resultant string, else add from the front.
- If the string is of even length, in the odd step add characters from the front and add characters from the back in the even step.
The reverse of the resultant string thus obtained is the original string which was encrypted.
Below is the implementation of the above approach:
C++
// C++ program to decrypt the original string #include <bits/stdc++.h> using namespace std; // Function to return the original string // after decryption string decrypt(string s, int l) { // Stores the decrypted string string ans = "" ; // If length is odd if (l % 2) { // Step counter int cnt = 0; // Starting and ending index int indl = 0, indr = l - 1; // Iterate till all characters // are decrypted while (ans.size() != l) { // Even step if (cnt % 2 == 0) ans += s[indl++]; // Odd step else ans += s[indr--]; cnt++; } } // If length is even else { // Step counter int cnt = 0; // Starting and ending index int indl = 0, indr = l - 1; while (ans.size() != l) { // Even step if (cnt % 2 == 0) ans += s[indr--]; // Odd step else ans += s[indl++]; cnt++; } } // Reverse the decrypted string reverse(ans.begin(), ans.end()); return ans; } // Driver Code int main() { string s = "segosegekfrek" ; int l = s.length(); cout << decrypt(s, l); return 0; } |
Java
// Java program to decrypt the original string import java.io.*; import java.util.*; class GFG { // Function to return the original string // after decryption public static String decrypt(String s, int l) { // Stores the decrypted string String ans = "" ; // If length is odd if (l % 2 == 1 ) { // Step counter int cnt = 0 ; // Starting and ending index int indl = 0 , indr = l - 1 ; // Iterate till all characters // are decrypted while (ans.length() != l) { // Even step if (cnt % 2 == 0 ) ans += s.charAt(indl++); // Odd step else ans += s.charAt(indr--); cnt++; } } // If length is even else { // Step counter int cnt = 0 ; // Starting and ending index int indl = 0 , indr = l - 1 ; while (ans.length() != l) { // Even step if (cnt % 2 == 0 ) ans += s.charAt(indr--); // Odd step else ans += s.charAt(indl++); cnt++; } } // Reverse the decrypted string StringBuffer sbr = new StringBuffer(ans); sbr.reverse(); return sbr.toString(); } // Driver code public static void main (String[] args) { String s = "segosegekfrek" ; int l = s.length(); System.out.println(decrypt(s, l)); } } // This Code is contributed by Manu Pathria |
Python3
# Python3 program to decrypt # the original string # Function to return the # original string after # decryption def decrypt(s, l): # Stores the decrypted # string ans = "" # If length is odd if (l % 2 ): # Step counter cnt = 0 # Starting and ending # index indl = 0 indr = l - 1 # Iterate till all # characters are decrypted while ( len (ans) ! = l): # Even step if (cnt % 2 = = 0 ): ans + = s[indl] indl + = 1 # Odd step else : ans + = s[indr] indr - = 1 cnt + = 1 # If length is even else : # Step counter cnt = 0 # Starting and ending # index indl = 0 indr = l - 1 while ( len (ans) ! = l): # Even step if (cnt % 2 = = 0 ): ans + = s[indr] indr - = 1 # Odd step else : ans + = s[indl] indl + = 1 cnt + = 1 # Reverse the decrypted # string string = list (ans) string.reverse() ans = ''.join(string) return ans # Driver Code if __name__ = = "__main__" : s = "segosegekfrek" l = len (s) print (decrypt(s, l)) # This code is contributed by Chitranayal |
C#
// C# program to decrypt the original string using System; using System.Collections; using System.Collections.Generic; class GFG { // Function to return the original string // after decryption static string decrypt( string s, int l) { // Stores the decrypted string string ans = "" ; // If length is odd if (l % 2 == 1) { // Step counter int cnt = 0; // Starting and ending index int indl = 0, indr = l - 1; // Iterate till all characters // are decrypted while (ans.Length != l) { // Even step if (cnt % 2 == 0) ans += s[indl++]; // Odd step else ans += s[indr--]; cnt++; } } // If length is even else { // Step counter int cnt = 0; // Starting and ending index int indl = 0, indr = l - 1; while (ans.Length != l) { // Even step if (cnt % 2 == 0) ans += s[indr--]; // Odd step else ans += s[indl++]; cnt++; } } // Reverse the decrypted string //Array.Reverse(ans); char [] sbr = ans.ToCharArray(); Array.Reverse(sbr); return new string (sbr); } // Driver code public static void Main () { string s = "segosegekfrek" ; int l = s.Length; Console.Write(decrypt(s, l)); } } // This Code is contributed by Samim Hossain Mondal. |
Javascript
<script> // JavaScript program to decrypt the original string // Function to return the original string // after decryption function decrypt( s , l) { // Stores the decrypted string var ans = "" ; // If length is odd if (l % 2 == 1) { // Step counter var cnt = 0; // Starting and ending index var indl = 0, indr = l - 1; // Iterate till all characters // are decrypted while (ans.length != l) { // Even step if (cnt % 2 == 0) ans += s.charAt(indl++); // Odd step else ans += s.charAt(indr--); cnt++; } } // If length is even else { // Step counter var cnt = 0; // Starting and ending index var indl = 0, indr = l - 1; while (ans.length != l) { // Even step if (cnt % 2 == 0) ans += s.charAt(indr--); // Odd step else ans += s.charAt(indl++); cnt++; } } // Reverse the decrypted string return ans.split( '' ).reverse().join( '' ); } // Driver code var s = "segosegekfrek" ; var l = s.length; document.write(decrypt(s, l)); // This code is contributed by todaysgaurav </script> |
w3wiki
Complexity Analysis:
- Time Complexity: O(N), as we are using a loop to traverse N times. Where N is the length of the string.
- Auxiliary Space: O(N), as we are using extra space for the string. Where N is the length of the string.
Below is Python’s implementation.
C++
#include <bits/stdc++.h> using namespace std; // Function for encryption string encrypted_string(string strg) { string EncryptedString = { strg[0] }; for ( int t = 1; t < strg.length(); t++) { if (t % 2 == 1) { EncryptedString.push_back( strg[t]); // At odd position, append the // next character } else { EncryptedString.insert( 0, 1, strg[t]); // At Even position, prepend // the next character } } // print the resultant string return EncryptedString; } // Function for decryption string decrypted_string(string strg) { // Check the divisibility of length of string by 2 if (strg.length() % 2 != 0) { string DecryptedString = { strg[0] }; for ( int t = 1; t < strg.length(); t++) { DecryptedString.push_back( strg[strg.length() - 1 - t]); // First add the characters from // the back DecryptedString.push_back( strg[t]); // from the front } reverse( DecryptedString.begin(), DecryptedString.end()); // Reverse the final // string to get output return DecryptedString; } else { string reverse_strg = strg; reverse( reverse_strg.begin(), reverse_strg .end()); // In case of even length, reverse // the given string first string DecryptedString = { reverse_strg[0] }; // Looping over the reversed string for ( int t = 1; t < reverse_strg.length(); t++) { DecryptedString.push_back( reverse_strg[reverse_strg.length() - 1 - t]); // First add the // characters from the // back DecryptedString.push_back( reverse_strg[t]); // and then from the front } reverse( DecryptedString.begin(), DecryptedString.end()); // Reverse the final // string to get output return DecryptedString; } } // Testing the algorithm with Driver Code int main() { cout << encrypted_string( "Beginner" ) << endl; cout << encrypted_string( "w3wiki" ) << endl; cout << encrypted_string( "strive" ) << endl; cout << encrypted_string( "vikaschitturi" ) << endl; cout << encrypted_string( "padmachitturi" ) << endl; cout << encrypted_string( "hackerrank" ) << endl; cout << encrypted_string( "hackerearth" ) << endl; cout << encrypted_string( "codechef" ) << endl; cout << encrypted_string( "IamVikas" ) << endl; cout << encrypted_string( "HelloHowareyou" ) << endl; cout << encrypted_string( "whatareyoudoing" ) << endl; cout << decrypted_string( "segek" ) << endl; cout << decrypted_string( "segosegekfrek" ) << endl; cout << decrypted_string( "vrstie" ) << endl; cout << decrypted_string( "iuthskviacitr" ) << endl; cout << decrypted_string( "iuthadpamcitr" ) << endl; cout << decrypted_string( "nrechakrak" ) << endl; cout << decrypted_string( "hreechakrat" ) << endl; cout << decrypted_string(encrypted_string( "IamVikas" )) << endl; cout << decrypted_string( encrypted_string( "HelloHowareyou" )) << endl; return 0; } |
Java
import java.util.*; public class GFG { // Function for encryption public static String encryptedString(String str) { StringBuilder encryptedString = new StringBuilder(); encryptedString.append(str.charAt( 0 )); for ( int t = 1 ; t < str.length(); t++) { if (t % 2 == 1 ) { encryptedString.append(str.charAt(t)); } else { encryptedString.insert( 0 , str.charAt(t)); } } return encryptedString.toString(); } // Function for decryption public static String decryptedString(String str) { if (str.length() % 2 != 0 ) { StringBuilder decryptedString = new StringBuilder(); decryptedString.append(str.charAt( 0 )); for ( int t = 1 ; t < str.length(); t++) { decryptedString.append(str.charAt(str.length() - 1 - t)); decryptedString.append(str.charAt(t)); } return decryptedString.reverse().toString(); } else { StringBuilder reverseStr = new StringBuilder(str).reverse(); StringBuilder decryptedString = new StringBuilder(); decryptedString.append(reverseStr.charAt( 0 )); for ( int t = 1 ; t < reverseStr.length(); t++) { decryptedString.append(reverseStr.charAt(reverseStr.length() - 1 - t)); decryptedString.append(reverseStr.charAt(t)); } return decryptedString.reverse().toString(); } } // Testing the algorithm with Driver Code public static void main(String[] args) { System.out.println(encryptedString( "Beginner" )); System.out.println(encryptedString( "w3wiki" )); System.out.println(encryptedString( "strive" )); System.out.println(encryptedString( "vikaschitturi" )); System.out.println(encryptedString( "padmachitturi" )); System.out.println(encryptedString( "hackerrank" )); System.out.println(encryptedString( "hackerearth" )); System.out.println(encryptedString( "codechef" )); System.out.println(encryptedString( "IamVikas" )); System.out.println(encryptedString( "HelloHowareyou" )); System.out.println(encryptedString( "whatareyoudoing" )); System.out.println(decryptedString( "segek" )); System.out.println(decryptedString( "segosegekfrek" )); System.out.println(decryptedString( "vrstie" )); System.out.println(decryptedString( "iuthskviacitr" )); System.out.println(decryptedString( "iuthadpamcitr" )); System.out.println(decryptedString( "nrechakrak" )); System.out.println(decryptedString( "hreechakrat" )); System.out.println(decryptedString(encryptedString( "IamVikas" ))); System.out.println(decryptedString(encryptedString( "HelloHowareyou" ))); } } |
Python3
#Python 3 Code for encrypting a string according to given rules #Function for encryption def encrypted_string(strg): EncryptedString = [strg[ 0 ]] for t in range ( 1 , len (strg)): if (t % 2 = = 1 ): EncryptedString.append(strg[t]) #At odd position, append the next character else : EncryptedString.insert( 0 ,strg[t]) #At Even position, prepend the next character #print the resultant string return (''.join(EncryptedString)) #Python 3 Code for decrypting a string (Answer to the actual question) def decrypted_string(strg): #CHeck the divisibility of length of string by 2 if ( len (strg) % 2 ! = 0 ): DecryptedString = [strg[ 0 ]] for t in range ( 1 , len (strg)): DecryptedString.append(strg[ - 1 * t]) #First add the characters from the back DecryptedString.append(strg[t]) #from the front DecryptedString = DecryptedString[: len (strg)][:: - 1 ] #Reverse the final string to get output return (''.join(DecryptedString)) else : reverse_strg = strg[:: - 1 ] #In case of even length, reverse the given string first DecryptedString = [reverse_strg[ 0 ]] #Looping over the reversed string for t in range ( 1 , len (reverse_strg)): DecryptedString.append(reverse_strg[ - 1 * t]) #First add the characters from the back DecryptedString.append(reverse_strg[t]) #and then from the front DecryptedString = DecryptedString[: len (reverse_strg)][:: - 1 ] return (''.join(DecryptedString)) #Testing the algorithm with Driver Code if __name__ = = '__main__' : print (encrypted_string( 'Beginner' )) print (encrypted_string( 'w3wiki' )) print (encrypted_string( 'strive' )) print (encrypted_string( 'vikaschitturi' )) print (encrypted_string( 'padmachitturi' )) print (encrypted_string( 'hackerrank' )) print (encrypted_string( 'hackerearth' )) print (encrypted_string( 'codechef' )) print (encrypted_string( 'IamVikas' )) print (encrypted_string( 'HelloHowareyou' )) print (encrypted_string( 'whatareyoudoing' )) print (decrypted_string( 'segek' )) print (decrypted_string( 'segosegekfrek' )) print (decrypted_string( 'vrstie' )) print (decrypted_string( 'iuthskviacitr' )) print (decrypted_string( 'iuthadpamcitr' )) print (decrypted_string( 'nrechakrak' )) print (decrypted_string( 'hreechakrat' )) print (decrypted_string(encrypted_string( 'IamVikas' ))) print (decrypted_string(encrypted_string( 'HelloHowareyou' ))) print (decrypted_string(encrypted_string( 'whatareyoudoing' ))) |
C#
using System; using System.Text; class Program { // Function for encryption static string EncryptedString( string str) { StringBuilder encryptedString = new StringBuilder(str[0].ToString()); for ( int i = 1; i < str.Length; i++) { if (i % 2 == 1) { encryptedString.Append(str[i]); // At odd position, append the next character } else { encryptedString.Insert(0, str[i].ToString()); // At even position, prepend the next character } } return encryptedString.ToString(); } // Function for decryption static string DecryptedString( string str) { if (str.Length % 2 != 0) { StringBuilder decryptedString = new StringBuilder(str[0].ToString()); for ( int i = 1; i < str.Length; i++) { decryptedString.Append(str[str.Length - 1 - i]); // First add the characters from the back decryptedString.Append(str[i]); // from the front } char [] charArray = decryptedString.ToString().ToCharArray(); Array.Reverse(charArray); return new string (charArray); } else { string reverseStr = new string (str.ToCharArray()); Array.Reverse(reverseStr.ToCharArray()); StringBuilder decryptedString = new StringBuilder(reverseStr[0].ToString()); for ( int i = 1; i < reverseStr.Length; i++) { decryptedString.Append(reverseStr[reverseStr.Length - 1 - i]); // First add the characters from the back decryptedString.Append(reverseStr[i]); // and then from the front } char [] charArray = decryptedString.ToString().ToCharArray(); Array.Reverse(charArray); return new string (charArray); } } static void Main() { Console.WriteLine(EncryptedString( "Beginner" )); Console.WriteLine(EncryptedString( "w3wiki" )); Console.WriteLine(EncryptedString( "strive" )); Console.WriteLine(EncryptedString( "vikaschitturi" )); Console.WriteLine(EncryptedString( "padmachitturi" )); Console.WriteLine(EncryptedString( "hackerrank" )); Console.WriteLine(EncryptedString( "hackerearth" )); Console.WriteLine(EncryptedString( "codechef" )); Console.WriteLine(EncryptedString( "IamVikas" )); Console.WriteLine(EncryptedString( "HelloHowareyou" )); Console.WriteLine(EncryptedString( "whatareyoudoing" )); Console.WriteLine(DecryptedString( "segek" )); Console.WriteLine(DecryptedString( "segosegekfrek" )); Console.WriteLine(DecryptedString( "vrstie" )); Console.WriteLine(DecryptedString( "iuthskviacitr" )); Console.WriteLine(DecryptedString( "iuthadpamcitr" )); Console.WriteLine(DecryptedString( "nrechakrak" )); Console.WriteLine(DecryptedString( "hreechakrat" )); Console.WriteLine(DecryptedString(EncryptedString( "IamVikas" ))); Console.WriteLine(DecryptedString(EncryptedString( "HelloHowareyou" ))); } } |
Javascript
// Function for encryption function encryptedString(strg) { let encryptedString = strg[0]; for (let t = 1; t < strg.length; t++) { if (t % 2 === 1) { encryptedString += strg[t]; } else { encryptedString = strg[t] + encryptedString; } } return encryptedString; } // Function for decryption function decryptedString(strg) { if (strg.length % 2 !== 0) { let decryptedString = strg[0]; for (let t = 1; t < strg.length; t++) { decryptedString += strg[strg.length - 1 - t]; decryptedString += strg[t]; } return decryptedString.split( '' ).reverse().join( '' ); } else { let reverseStrg = strg.split( '' ).reverse().join( '' ); let decryptedString = reverseStrg[0]; for (let t = 1; t < reverseStrg.length; t++) { decryptedString += reverseStrg[reverseStrg.length - 1 - t]; decryptedString += reverseStrg[t]; } return decryptedString.split( '' ).reverse().join( '' ); } } // Testing the algorithm with Driver Code console.log(encryptedString( "Beginner" )); console.log(encryptedString( "w3wiki" )); console.log(encryptedString( "strive" )); console.log(encryptedString( "vikaschitturi" )); console.log(encryptedString( "padmachitturi" )); console.log(encryptedString( "hackerrank" )); console.log(encryptedString( "hackerearth" )); console.log(encryptedString( "codechef" )); console.log(encryptedString( "IamVikas" )); console.log(encryptedString( "HelloHowareyou" )); console.log(encryptedString( "whatareyoudoing" )); console.log(decryptedString( "segek" )); console.log(decryptedString( "segosegekfrek" )); console.log(decryptedString( "vrstie" )); console.log(decryptedString( "iuthskviacitr" )); console.log(decryptedString( "iuthadpamcitr" )); console.log(decryptedString( "nrechakrak" )); console.log(decryptedString( "hreechakrat" )); console.log(decryptedString(encryptedString( "IamVikas" ))); console.log(decryptedString(encryptedString( "HelloHowareyou" ))); |
segek segosegekfrek vrstie iuthskviacitr iuthadpamcitr nrechakrak hreechakrat ecdcoehf aimIaVks oeaoolHelHwryu gidoeaawhtryuon Beginner w3wiki strive vikaschitturi padmachitturi hackerrank hackerearth IamVikas HelloHowareyou whatareyoudoing
Complexity Analysis:
- Time Complexity: O(N), as we are using a loop to traverse N times. Where N is the length of the string.
- Auxiliary Space: O(N), as we are using extra space. Where N is the length of the string.
Approach: Using 2 pointers
C++
#include <bits/stdc++.h> using namespace std; string decrypt(string encrypted_string) { int i = 0; int n = encrypted_string.size(); int j = n - 1; string decrypted_string = "" ; if (n % 2 == 1) { while (i < j) { decrypted_string = encrypted_string[i] + decrypted_string; decrypted_string = encrypted_string[j] + decrypted_string; i++; j--; } decrypted_string = encrypted_string[i] + decrypted_string; } else { while (i < j) { decrypted_string = encrypted_string[j] + decrypted_string; decrypted_string = encrypted_string[i] + decrypted_string; i++; j--; } } return decrypted_string; } int main() { cout << (decrypt( "segosegekfrek" )) << endl; cout << (decrypt( "vrstie" )) << endl; cout << (decrypt( "segek" )) << endl; } // This code is contributed by garg28harsh. |
Java
/*package whatever //do not write package name here */ import java.util.*; public class Solution { static String decrypt(String encrypted_string) { int i = 0 ; int n = encrypted_string.length(); int j = n - 1 ; String decrypted_string = "" ; if (n % 2 == 1 ) { while (i < j) { decrypted_string = encrypted_string.charAt(i) + decrypted_string; decrypted_string = encrypted_string.charAt(j) + decrypted_string; i++; j--; } decrypted_string = encrypted_string.charAt(i) + decrypted_string; } else { while (i < j) { decrypted_string = encrypted_string.charAt(j) + decrypted_string; decrypted_string = encrypted_string.charAt(i) + decrypted_string; i++; j--; } } return decrypted_string; } public static void main(String[] args) { System.out.println(decrypt( "segosegekfrek" )); System.out.println(decrypt( "vrstie" )); System.out.println(decrypt( "segek" )); } } // This code is contributed by karandeep1234 |
Python3
def decrypt(encrypted_string): i = 0 n = len (encrypted_string) j = n - 1 decrypted_string = '' if n % 2 = = 1 : while i < j: decrypted_string = encrypted_string[i] + decrypted_string decrypted_string = encrypted_string[j] + decrypted_string i + = 1 j - = 1 decrypted_string = encrypted_string[i] + decrypted_string else : while i < j: decrypted_string = encrypted_string[j] + decrypted_string decrypted_string = encrypted_string[i] + decrypted_string i + = 1 j - = 1 return decrypted_string # Testing sample inputs if __name__ = = '__main__' : print (decrypt( 'segosegekfrek' )) # should print w3wiki print (decrypt( 'vrstie' )) # should print strive print (decrypt( 'segek' )) # should print Beginner |
C#
using System; public class GFG { static string decrypt( string encrypted_string) { int i = 0; int n = encrypted_string.Length; int j = n - 1; String decrypted_string = "" ; if (n % 2 == 1) { while (i < j) { decrypted_string = encrypted_string[i] + decrypted_string; decrypted_string = encrypted_string[j] + decrypted_string; i++; j--; } decrypted_string = encrypted_string[i] + decrypted_string; } else { while (i < j) { decrypted_string = encrypted_string[j] + decrypted_string; decrypted_string = encrypted_string[i] + decrypted_string; i++; j--; } } return decrypted_string; } public static void Main( string [] args) { Console.WriteLine(decrypt( "segosegekfrek" )); Console.WriteLine(decrypt( "vrstie" )); Console.WriteLine(decrypt( "segek" )); } } // This code is contributed by karandeep1234 |
Javascript
function decrypt(encrypted_string) { let i = 0; let n = encrypted_string.length; let j = n - 1; let decrypted_string = "" ; if (n % 2 == 1) { while (i < j) { decrypted_string = encrypted_string[i] + decrypted_string; decrypted_string = encrypted_string[j] + decrypted_string; i++; j--; } decrypted_string = encrypted_string[i] + decrypted_string; } else { while (i < j) { decrypted_string = encrypted_string[j] + decrypted_string; decrypted_string = encrypted_string[i] + decrypted_string; i++; j--; } } return decrypted_string; } console.log(decrypt( "segosegekfrek" )); console.log(decrypt( "vrstie" )); console.log(decrypt( "segek" )); // This code is contributed by Samim Hossain Mondal. |
w3wiki strive Beginner
Complexity Analysis:
- Time Complexity: O(N), as we are using a loop to traverse N times. Where N is the length of the string.
- Auxiliary Space: O(N), as we are using extra space. Where N is the length of the string.
Decrypt a string according to given rules:
Approach:
1. Define a function “decrypt” that takes the “ciphertext” string as input.
2. Iterate over all the possible 26 shifts.
3. For each shift, create an empty string “decrypted”.
4. Iterate over each character in the “ciphertext” string.
5. If the character is an alphabet, then shift it using the current shift value and add it to the “decrypted” string.
6. If the character is not an alphabet, then add it directly to the “decrypted” string.
7. Print the current shift value and the decrypted message for that shift.
8. Time complexity: O(n^2) where n is the length of the “ciphertext” string since we are iterating over all the possible 26 shifts for each character in the string.
9. Space complexity: O(n) since we are creating a new string “decrypted” for each shift.
C++
#include <iostream> #include <string> using namespace std; void decrypt(string ciphertext) { for ( int shift = 0; shift < 26; shift++) { string decrypted = "" ; for ( char & c : ciphertext) { if ( isalpha (c)) { if ( isupper (c)) { decrypted += ((c - shift - 'A' + 26) % 26) + 'A' ; } else { decrypted += ((c - shift - 'a' + 26) % 26) + 'a' ; } } else { decrypted += c; } } cout << "Shift: " << shift << ", Decrypted message: " << decrypted << endl; } } int main() { string ciphertext = "Khoor, zruog!" ; decrypt(ciphertext); return 0; } |
Java
import java.util.*; public class Main { public static void decrypt(String ciphertext) { for ( int shift = 0 ; shift < 26 ; shift++) { String decrypted = "" ; for ( char c : ciphertext.toCharArray()) { if (Character.isLetter(c)) { if (Character.isUpperCase(c)) { decrypted += ( char ) (((c - shift - 'A' + 26 ) % 26 ) + 'A' ); } else { decrypted += ( char ) (((c - shift - 'a' + 26 ) % 26 ) + 'a' ); } } else { decrypted += c; } } System.out.println( "Shift: " + shift + ", Decrypted message: " + decrypted); } } public static void main(String[] args) { String ciphertext = "Khoor, zruog!" ; decrypt(ciphertext); } } |
Python3
def decrypt(ciphertext): for shift in range ( 26 ): decrypted = "" for char in ciphertext: if char.isalpha(): if char.isupper(): decrypted + = chr (( ord (char) - shift - 65 ) % 26 + 65 ) else : decrypted + = chr (( ord (char) - shift - 97 ) % 26 + 97 ) else : decrypted + = char print (f "Shift: {shift}, Decrypted message: {decrypted}" ) ciphertext = "Khoor, zruog!" decrypt(ciphertext) |
C#
using System; class Program { static void Main( string [] args) { string ciphertext = "Khoor, zruog!" ; // The encrypted message Decrypt(ciphertext); // Call the Decrypt function // with the encrypted message // as an argument } static void Decrypt( string ciphertext) { for ( int shift = 0; shift < 26; shift++) // Loop through all possible shifts { string decrypted = "" ; // Initialize an empty string to store // the decrypted message foreach ( char c in ciphertext) // Loop through each // character in the // encrypted message { if ( char .IsLetter( c)) // Check if the character is a // letter { if ( char .IsUpper( c)) // Check if the letter is // uppercase { decrypted += ( char )(((c - shift - 'A' ) + 26) % 26 + 'A' ); // Decrypt // uppercase // letters // using the // shift value } else { decrypted += ( char )(((c - shift - 'a' ) + 26) % 26 + 'a' ); // Decrypt // lowercase // letters // using the // shift value } } else { decrypted += c; } } Console.WriteLine( "Shift: " + shift + ", Decrypted message: " + decrypted); // Print the shift value and // decrypted message for each // possible shift value } } } |
Javascript
function decrypt(ciphertext) { for (let shift = 0; shift < 26; shift++) { let decrypted = "" ; for (let i = 0; i < ciphertext.length; i++) { let char = ciphertext.charAt(i); if (char.match(/[a-z]/i)) { if (char === char.toUpperCase()) { decrypted += String.fromCharCode((char.charCodeAt(0) - shift - 65 + 26) % 26 + 65); } else { decrypted += String.fromCharCode((char.charCodeAt(0) - shift - 97 + 26) % 26 + 97); } } else { decrypted += char; } } console.log(`Shift: ${shift}, Decrypted message: ${decrypted}`); } } let ciphertext = "Khoor, zruog!" ; decrypt(ciphertext); |
...: 3, Decrypted message: Hello, world! Shift: 4, Decrypted message: Gdkkn, vnqkc! Shift: 5, Decrypted message: Fcjjm, umpjb! Shift: 6, Decrypted message: Ebiil, tloia! Shift: 7, Decrypted message: Dahhk, sknhz! Shift: 8, Decrypted message: Czggj, rjmgy! Shift: 9, Decrypted message: Byffi, qilfx! Shift: 10, Decrypted message: Axeeh, phkew! Shift: 11, Decrypted message: Zwddg, ogjdv! Shift: 12, Decrypted message: Yvccf, nficu! Shift: 13, Decrypted message: Xubbe, mehbt! Shift: 14, Decrypted message: Wtaad, ldgas! Shift: 15, Decrypted message: Vszzc, kcfzr! Shift: 16, Decrypted message: Uryyb, jbeyq! Shift: 17, Decrypted message: Tqxxa, iadxp! Shift: 18, Decrypted message: Spwwz, hzcwo! Shift: 19, Decrypted message: Rovvy, gybvn! Shift: 20, Decrypted message: Qnuux, fxaum! Shift: 21, Decrypted message: Pmttw, ewztl! Shift: 22, Decrypted message: Olssv, dvysk! Shift: 23, Decrypted message: Nkrru, cuxrj! Shift: 24, Decrypted message: Mjqqt, btwqi! Shift: 25, Decrypted message: Lipps, asvph!
The time complexity of the “decrypt” function in the given Python code is O(n * 26), where n is the length of the input “ciphertext” string. This is because the function iterates over all the 26 possible shift values and for each shift value, it iterates over each character in the “ciphertext” string.
The auxiliary space of the function is also O(n * 26), where n is the length of the input “ciphertext” string. This is because for each shift value, a new string “decrypted” is created and its length is equal to the length of the “ciphertext” string. Therefore, the total space required by the function is proportional to the product of the length of the “ciphertext” string and the number of shift values, which is 26 in this case.
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