Decimal.ToDouble() Method in C#
This method is used to convert the value of the specified Decimal to the equivalent double-precision floating-point number. This method can produce round-off errors as a double-precision floating-point number has few significant digits than a Decimal.
Syntax: public static double ToDouble (decimal d);
Here, d is the decimal value which is to be converted.Return value: It returns a double-precision floating-point number equivalent to d.
Example:
// C# program to demonstrate the // Decimal.ToDouble(Decimal) Method using System; class GFG { // Main Method public static void Main() { try { // Taking decimal variables Decimal dec1 = 0.0000000000134563456789M; Decimal dec2 = 4589662514452860951234M; // using ToDouble(Decimal) Method Double val1 = Decimal.ToDouble(dec1); // using ToDouble(Decimal) Method Double val2 = Decimal.ToDouble(dec2); // Printing the Double value Console.WriteLine( "The Double value " + "is : {0}" , val1); // Printing the Double value Console.WriteLine( "The Double value " + "is : {0}" , val2); } catch (OverflowException e) { Console.Write( "Exception Thrown: " ); Console.Write( "{0}" , e.GetType(), e.Message); } } } |
Output:
The Double value is : 1.34563456789E-11 The Double value is : 4.58966251445286E+21
Reference:
- https://docs.microsoft.com/en-us/dotnet/api/system.decimal.todouble?view=netframework-4.7.2
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