8086 program to convert a 16 bit decimal number to Hexadecimal
Problem: We are given a 16 bit decimal number we have to print the number in Hexadecimal format.
Examples:
Input: d1 = 999 Output: 3E7 Input: d1 = 123 Output: 7B
Explanation:
- Load the value stored into register
- Divide the value by 16 to convert it to Hexadecimal
- Push the remainder into the stack
- Increase the count
- Repeat the steps until the value of the register is greater than 0
- Until the count is greater than zero
- POP the stack
- If the value of top of stack is greater than 9
- Then add 7 more to the value so that they correspond to HEX characters A, B, C, D, E, F
- Add 48 to the top element to convert it into ASCII
- Print the character using interrupt
- Decrements the count
Program:
;8086 program to convert a 16 bit decimal number to Hexadecimal .MODEL SMALL .STACK 100H .DATA d1 dw 999 .CODE MAIN PROC FAR MOV AX, @DATA MOV DS, AX ;load the value stored; in variable d1 mov ax, d1 ;convert the value to Hexadecimal; print the value CALL PRINT ;interrupt to exit MOV AH, 4CH INT 21H MAIN ENDP PRINT PROC ;initialize count mov cx, 0 mov dx, 0 label1: ; if ax is zero cmp ax, 0 je print1 ;initialize bx to 16 mov bx, 16 ;divide it by 16 ;to convert it to Hexadecimal div bx ;push it in the stack push dx ;increment the count inc cx ;set dx to 0 xor dx, dx jmp label1 print1: ;check if count ;is greater than zero cmp cx, 0 je exit ;pop the top of stack pop dx ;compare the value ;with 9 cmp dx, 9 jle continue ; if value is greater than 9 ;then add 7 so that after ;adding 48 it represents A ; for example 10 + 7 + 48 = 65 ;which is ASCII value of A add dx, 7 continue : ;add 48 so that it ;represents the ASCII ;value of digits add dx, 48 ;interrupt to print a; character mov ah, 02h int 21h ;decrease the count dec cx jmp print1 exit : ret PRINT ENDP END MAIN |
Output:
3E7
Note: The program cannot be run on an online editor, please use MASM to run the program and use dos box to run MASM, you might use any 8086 emulator to run the program
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